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9 July, 13:38

Which shows the correct substitution of the values a, b, and c from the equation 0 = - 3x2 - 2x + 6 into the quadratic formula? Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3) (6) EndRoot Over 2 (negative 3) EndFraction x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4 (negative 3) (6) EndRoot Over 2 (negative 3) EndFraction x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3) (6) EndRoot Over 2 (3) EndFraction x = StartFraction negative 2 plus or minus StartRoot 2 squared minus 4 (3) (6) EndRoot Over 2 (3) EndFraction

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  1. 9 July, 13:50
    0
    x = StartFraction negative

    (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3) (6) EndRoot Over 2 (negative 3) EndFraction

    Step-by-step explanation:

    0 = - 3x2 - 2x + 6

    It can still be written as

    - 3x2 - 2x + 6 = 0

    Quadratic formula=

    -b+or-√b^2-4ac/2a

    Where

    a=-3

    b=-2

    c=6

    x = - (-2) + or-√ (-2) ^2-4 (-3) (6) / 2 (-3)

    x = StartFraction negative

    (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3) (6) EndRoot Over 2 (negative 3) EndFraction
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