Which function can be used to find the number of cells of bacteria in the population at time t

db / dt = kb

this becomes b (t) = Ce^ (kt)

C = 100, the initial population

P (1) = 420 = 100 e^ (1k)

4.2 = e^k

ln 4.2 = k

a) thus, b (t) = 100 e^ (t ln 4.2)

b) b (3) = 100 e^ (3 ln 4.2)

c) growth constant will still be ln 4.2 (constant percentage of populatioin)

d) 10000 = 100 e^ (t ln 4.2)

100 = e^ (t ln 4.2)

ln 100 = t ln 4.2

t = ln 100 / ln 4.2