Translate ƒ (x) = |x| so that it's translated down by 2 units and to the left 6 units. What's the new function g (x) ? A) g (x) = |x - 6| + 2

B) g (x) = |x - 6| - 2

C) g (x) = |x + 6| + 2

D) g (x) = |x + 6| - 2

Question

Mathematics

Guest

8 March, 10:28

Translate ƒ (x) = |x| so that it's translated down by 2 units and to the left 6 units. What's the new function g (x) ? A) g (x) = |x - 6| + 2

B) g (x) = |x - 6| - 2

C) g (x) = |x + 6| + 2

D) g (x) = |x + 6| - 2

+3

Answers (2)

Know the Answer?

Kameron Chaney · Answer 1

D) g (x) = |x + 6| - 2

Step-by-step explanation:

To translate f (x) h units to the right and k units up, you use the transformation ...

g (x) = f (x - h) + k

You want to translate your function 6 units left and 2 units down, so (h, k) = (-6, - 2) and the transformed function is ...

g (x) = |x + 6| - 2

Jazmine Mayo · Answer 2

D) g (x) = |x + 6| - 2

Translate ƒ (x) = |x| so that it's translated down by 2 units and to the left 6 units. What's the new function g (x) ? A) g (x) = |x - 6| + 2B) g (x) = |x - 6| - 2C) g (x) = |x + 6| + 2D) g (x) = |x + 6| - 2

Translate ƒ (x) = |x| so that it's translated down by 2 units and to the left 6 units. What's the new function g (x) ? A) g (x) = |x - 6| + 2

B) g (x) = |x - 6| - 2

C) g (x) = |x + 6| + 2

D) g (x) = |x + 6| - 2