Ask Question
5 March, 23:50

Determine the function's value when x = - 1.

g (x) = x3 + 6x2 + 12x + 8

+2
Answers (1)
  1. 6 March, 02:04
    0
    g (-1) = 1

    Step-by-step explanation:

    Using " ^ " to denote exponentiation, we get:

    g (x) = x^3 + 6x^2 + 12x + 8

    Substituting - 1 for x, we get:

    g (-1) = (-1) ^3 + 6 (-1) ^2 + 12 (-1) + 8, or

    g (-1) = - 1 + 6 - 12 + 8, or

    g (-1) = 1
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Determine the function's value when x = - 1. g (x) = x3 + 6x2 + 12x + 8 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers