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26 June, 00:41

Is g (x) = x (x - 4) [x-i (Square root of 7) ][x+i (Square root of 7) ] the factored form of f (x) = x^4+4x^3+7x^2+28x

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  1. 26 June, 03:11
    0
    No.

    It's x^4 - 4x^3 + 7x^2 - 28x.

    Step-by-step explanation:

    (x - √7 i) (x + √7i)

    = x^2 + √7x i - √7x i - 7 i^2

    = x^2 - 7 * - 1

    = x^2 + 7

    g (x) = x (x - 4) (x^2 + 7)

    = x (x^3 + 7x - 4x^2 - 28)

    = x^4 - 4x^3 + 7x^2 - 28x.
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