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23 January, 14:04

Solve for x if 2 (5x + 2) 2 = 48. x = StartFraction negative 2 + 2 StartRoot 24 EndRoot Over 5 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 24 EndRoot Over 5 EndFraction x = StartFraction negative 2 + 2 StartRoot 24 EndRoot Over 2 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 24 EndRoot Over 2 EndFraction x = StartFraction negative 2 + 2 StartRoot 6 EndRoot Over 5 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 6 EndRoot Over 5 EndFraction x = StartFraction negative 2 + 2 StartRoot 6 EndRoot Over 2 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 6 EndRoot Over 2 EndFraction

+1
Answers (2)
  1. 23 January, 14:36
    0
    Answer: c

    Step-by-step explanation:

    just did this
  2. 23 January, 15:28
    0
    x = (-2 ±2sqrt (6)) / 5

    Step-by-step explanation:

    2 (5x + 2) ^2 = 48.

    Divide each side by 2

    2/2 (5x + 2) ^2 = 48/2

    (5x + 2) ^2 = 24

    Take the square root of each side

    sqrt ((5x + 2) ^2) = ±sqrt (24)

    (5x + 2) = ±sqrt (6*4)

    5x+2 = ±sqrt (6) sqrt (4)

    5x+2 = ±2sqrt (6)

    Subtract 2 from each side

    5x+2-2 = -2 ±2sqrt (6)

    5x = -2 ±2sqrt (6)

    Divide each side by 5

    5x/5 = (-2 ±2sqrt (6)) / 5

    x = (-2 ±2sqrt (6)) / 5
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Home » Mathematics » Solve for x if 2 (5x + 2) 2 = 48. x = StartFraction negative 2 + 2 StartRoot 24 EndRoot Over 5 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 24 EndRoot Over 5 EndFraction x =
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