The sum of

5 consecutive integers is

110

What is the fourth number in this sequence?

Hello from MrBillDoesMath!

Answer: 23

Steps:

Let "n" be the smallest integer in the set of 5 consecutive integer. Then

n + (n+1) + (n+2) + (n+3) + (n+4) = 110.

Simplifying gives

5n + (1 + 2 + 3 + 4) = 110 or

5n + 10 = 110. Subtracting 10 from each side gives

5n = 110-10 = 100

So n = 20, and the fourth number in the (n+3) or 20+3 or 23

Regards, MrB