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6 July, 15:54

My geometric sequence is 16,-3.2,0.64,-0.128 ... what is the 7th term

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  1. 6 July, 16:59
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    Step-by-step explanation:

    In a geometric sequence, the nth term is

    T_n = ar^ (n-1)

    a = first term

    r = common ratio which can be gotten by dividing second term by first term, third term by second term etc

    Therefore

    a = 16

    r = - 3.2 : 16

    r = - 0.2

    T_7 = ar^ (7-1)

    T_7 = ar^6

    T_7 = 16[ (-0.2) ^6]

    T_7 = 16 (0.000064)

    T_7 = 0.001024
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