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19 July, 07:00

What is the solution to the system of equations 16x-2-2y=0 y=8x+4

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  1. 19 July, 07:31
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    No solution.

    Step-by-step explanation:

    To find the solution to the system, substitute the equation y = 8x + 4 into the equation 16x - 2 - 2y = 0.

    16x - 2 - 2 (8x+4) = 0

    16x - 2 - 16x - 8 = 0

    -2 - 8 = 0

    -10 = 0

    This statement is false. This means the system has no solution.
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