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28 January, 11:20

the angle of elevation of the top of a tree from a distance of 1000 ft is 25 degrees. how tall is the tree?

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  1. 28 January, 13:44
    0
    466.30 ft

    Step-by-step explanation:

    Given in the question,

    the angle of elevation of the top of a tree from ground = 25°

    horizontal distance between angle of elevation and tree = 1000ft

    To find,

    height of tree (vertical distance from ground to top of tree)

    As we can presume for the question that the whole scenario makes a right angle triangle. So, we will use trigonometry functions

    Tan Δ = opposite / adjacent

    Tan25° = height / 1000

    height = 1000 * Tan25°

    height = 1000 * 0.466

    height = 466.30 ft

    So, the height of tree = 466.30 ft
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