Ask Question
16 January, 22:47

My street hockey team plays three games each week. My team lost all $12$ games in the first four weeks. Then, my team won two games and lost one game in the fifth week, bringing our record to $2$ wins and $13$ losses. Each week after that, my team won two games and lost one game. My team first wins at least $60/%$ of its games by the end of $n$ weeks. What is $n$?

+2
Answers (1)
  1. 17 January, 01:57
    0
    At the end of the 10 th week

    Step-by-step explanation:

    My team plays 3 games and lost all of them (12 $) in the first 4 week

    so in 4 weeks my team lost 12 $ and all the games

    Then total games in three weeks is 4 * 3 = 12

    Total lost 12$ then we have a one dolar bet

    In the 5th week my team wins 2$ (two games) and at the end of 5th week record is:

    From 15 games my team won 2 games and lost 13 games and from that on, my team always wins 2 games then:

    Let call x number of week after the 5th then

    2 + 2*x / 15 + x = 0,6 0,6 = 60 %

    Solving for x

    2 + 2*x = 0,6 * (15 + x)

    2 + 2*x = 9 + 0,6 * x

    2*x - 0,6*x = 9 - 2

    2*x - 0,6*x = 7

    1,4*x = 7

    x = 7/1,4

    x = 5 weks later

    Then the answer is 10 weeks
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “My street hockey team plays three games each week. My team lost all $12$ games in the first four weeks. Then, my team won two games and ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers