Ask Question
18 May, 21:28

The length of a room is 8 ft greater than it is width. If each dimension is

increased by 2 ft, the area will be increased by 60 sq. ft. Find the dimensions of

the rooms.

+4
Answers (1)
  1. 19 May, 00:29
    0
    Answer

    Let width be equal to 'x'

    Length = x + 8

    Old area = x (x+8)

    Now, dimension increases

    Length = (x+10)

    width = x + 2

    New area = (x+2) (x+10)

    New area - old area = 60

    ((x+2) (x+10)) - (x (x+8)) = 60

    4x + 20 = 60

    4x = 40

    x = 10 ft

    Length of original room = 10+8 = 18 ft

    Width of original room = 10 ft.

    Length of increased dimension = 18 + 2 = 20 ft

    Width of increased dimension = 10 + 2 = 12 ft.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The length of a room is 8 ft greater than it is width. If each dimension is increased by 2 ft, the area will be increased by 60 sq. ft. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers