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Mathematics
Gwendolyn Richardson
12 March, 09:18
What is the factored form of the expression?
d^2 - 14d + 49
+5
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Kirsten Kent
12 March, 10:15
0
d^2 - 14d + 49 = (d-7) (d-7).
Step-by-step explanation:
Given the expression is d^2 - 14d + 49.
d^2 - 14d + 49 = d^2 - 2*7*d + 7^2
We know the formula of square of difference as given below:-
x^2 - 2*x*y + y^2 = (x-y) ^2
Using the above formula in the problem, here x = d and y = 7.
d^2 - 2*7*d + 7^2 = (d-7) ^2
d^2 - 2*7*d + 7^2 = (d-7) (d-7)
So, d^2 - 14d + 49 = (d-7) (d-7).
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Brandt
12 March, 11:56
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(d-7) (d-7)
Step-by-step explanation:
We have to make factored form of the expression.
Given expression is:
d²-14d+49
Split the middle term to make the equation into two groups such that the sum of 2 numbers should be - 14 and their product be 49.
d²-7d-7d+49
Making two groups and taking the common term out:
d (d-7) - 7 (d-7)
Take (d-7) common
(d-7) (d-7) which is factored form of d²-14d+49.
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