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12 March, 09:18

What is the factored form of the expression?

d^2 - 14d + 49

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Answers (2)
  1. 12 March, 10:15
    0
    d^2 - 14d + 49 = (d-7) (d-7).

    Step-by-step explanation:

    Given the expression is d^2 - 14d + 49.

    d^2 - 14d + 49 = d^2 - 2*7*d + 7^2

    We know the formula of square of difference as given below:-

    x^2 - 2*x*y + y^2 = (x-y) ^2

    Using the above formula in the problem, here x = d and y = 7.

    d^2 - 2*7*d + 7^2 = (d-7) ^2

    d^2 - 2*7*d + 7^2 = (d-7) (d-7)

    So, d^2 - 14d + 49 = (d-7) (d-7).
  2. 12 March, 11:56
    0
    (d-7) (d-7)

    Step-by-step explanation:

    We have to make factored form of the expression.

    Given expression is:

    d²-14d+49

    Split the middle term to make the equation into two groups such that the sum of 2 numbers should be - 14 and their product be 49.

    d²-7d-7d+49

    Making two groups and taking the common term out:

    d (d-7) - 7 (d-7)

    Take (d-7) common

    (d-7) (d-7) which is factored form of d²-14d+49.
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