What is the factored form of the expression?

12g2 + g - 6

The factored form is 12g^2 + g - 6 = (3g-2) * (4g + 3).

Step-by-step explanation:

Given the expression is 12g^2 + g - 6.

the product of a*c = - 72.

and the factors of b = + 9 - 8 = 1.

So, 12g^2 + g - 6 = 12g^2 + 9g - 8g - 6.

12g^2 + g - 6 = 3g * (4g + 3) - 2 * (4g + 3).

12g^2 + g - 6 = (3g-2) * (4g + 3).

Hence, the factored form is 12g^2 + g - 6 = (3g-2) * (4g + 3).

(4g+3) (3g-2)

Step-by-step explanation:

We have to make factored form of the expression.

Given expression is:

12g²+g-6

Split the middle term to make the equation into two groups such that the sum of 2 numbers should be 1 and their product be - 72.

12g²+9g-8g-6

Making two groups and taking the common term out:

3g (4g+3) - 2 (4g+3)

Take (4g+3) common

(4g+3) (3g-2) which is factored form of 12g²+g-6.