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20 June, 16:22

The athletic department at pi high is planning circular track it is 400 m long. The area inside will be planted with sod. How much sod do I need?

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  1. 20 June, 16:56
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    15,400tds^2

    Step-by-step explanation:

    440 = Pi x 2r (Diameter = 2 x radius)

    Radius = 440/2 x Pi

    Area of circle = Pi x (440/2 x Pi) ^2

    Area of circle = 15406. i9 yds^2

    = 15,400 yds^2 (nearest 100 yd^2)
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