For which equation will the solutions be opposite integers?

A 3x^2 - 27 = 0

B. 4x^2 + 20x+25

C. x^2 + 10x + 16 = 0

D. 2x^2 + 6x + 4 = 0

D. 2x^2 + 6x + 4 = 0

Step-by-step explanation:

The quadratic equation 2x²+6x+4 = 0 solutions will have opposite integers as shown.

On factorising:

2x²+6x+4 = 0

(2x²+2x) + (4x+4) = 0

Bringing out the common factor

2x (x+1) + 4 (x+1) = 0

(2x+4) + (x+1) = 0

2x+4 = 0 and x+1 = 0

2x = - 4 and x = - 1

x = - 1/2 and - 1

As we can see, the solution to the quadratic equation gave us two different integers. Note that the remaining functions will give the same values as the solutions.