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5 September, 23:30

A 13 L solution that was 12% vinegar was mixed with a 9 L solution that was 70% vinegar. What is the concentration of the new mixture?

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  1. 6 September, 02:19
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    The concentration is simply 36%

    Step-by-step explanation:

    In this question, we are concerned with calculating the concentration of a new mixture formed from mixing some liters of each of two vinegar variants of different concentrations.

    We proceed as follows;

    The concentration of the new solution will contain 12% of 13L vinegar A and 70% of 9L vinegar B

    13L of vinegar A will contain 13 * 12% = 13 * 0.12 = 1.56

    9L of 70% vinegar B will contain 9 * 70% = 9 * 0.7 = 6.3

    Now, the new mixture has a total volume of 13 + 9 = 22L

    The concentration of the new mixture will thus be;

    (1.56 + 6.3) / 22

    = 0.357 and that's approximately 0.36 or simply 36%
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