The axis of symmetry for the graph of the function f (x) = 3x2+bx+4 is x equals three-halves. What is the value of b? - 18 - 9 9 18

Answer: B ( - 9)

Step-by-step explanation: given the function f (x) = 3x^2 + bx + 4

And the axis of symmetry x = 3/2

The formula to calculate the axis of symmetry is:

X = - b/2a

Where

X = 3/2

a = 3

Substitute X and a into the formula

3/2 = - b / (2*3)

3/2 = - b/6

Cross multiply

-2b = 18

b = - 18/2

b = - 9

Therefore, the value of b is - 9