Given: y=x^2-4x-12

A.) determine the roots/zero

(By factoring & setting the answer equal to zero)

B.) use h=-b/2a to get vertex

see below

Step-by-step explanation:

y=x^2-4x-12

Set equal to 0 to find the zeros

0 = x^2-4x-12

Factor. What 2 numbers multiply to - 12 and add to - 4

-6*2 = - 12

-6+2 = - 4

0 = (x-6) (x+2)

Using the zero product property

0=x-6 0 = x+2

x=6 x = - 2

zeros: - 2,6

Vertex

h = - b/2a = - (-4) / 2 (1) = 4/2 = 2

OR Average the roots (-2+6) / 2 = 4/2 = 2

The y coordinate is found by substituting into the equation

y = (2) ^2 - 4 (2) - 12

y = 4-8-12

y = -16

vertex : (2, - 16)

x = - 2, 6

Vertex: (2,-16)

Step-by-step explanation:

x² - 4x - 12

x² - 6x + 2x - 12

x (x - 6) + 2 (x - 6)

(x - 6) (x + 2) = 0

x = - 2, 6

h = - (-4) / 2

h = 4/2

h = 2

k = 2² - 4 (2) - 12

k = 4 - 8 - 12

k = - 16

Vertex: (2,-16)