The length of a rectangle is 8 cm more than 3 times its width. The perimeter of the rectangle is 64 cm. Show the equation that would be used to find the dimensions of the rectangle.

Let w = the width. Then 3w = length + 8. So the equation is 64 = 2 (3w - 8) + 2w.

Let w = the width. Then 3w + 8 = length. So the equation is 64 = 2 (3w + 8) + 2w. 64 = 2 (3w + 8) + 2w

Let w = the width. Then 3 (w + 8) = length. So the equation is 64 = 2 (3 (w + 8)) + 2w.

Let w = the width. Then 3w + 8 = length. So the equation is 64 = (3w + 8) w.

Question

Mathematics

Louis Mann

29 June, 12:59

The length of a rectangle is 8 cm more than 3 times its width. The perimeter of the rectangle is 64 cm. Show the equation that would be used to find the dimensions of the rectangle.

Let w = the width. Then 3w = length + 8. So the equation is 64 = 2 (3w - 8) + 2w.

Let w = the width. Then 3w + 8 = length. So the equation is 64 = 2 (3w + 8) + 2w. 64 = 2 (3w + 8) + 2w

Let w = the width. Then 3 (w + 8) = length. So the equation is 64 = 2 (3 (w + 8)) + 2w.

Let w = the width. Then 3w + 8 = length. So the equation is 64 = (3w + 8) w.

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Answers (1)

Know the Answer?

Fernanda Jacobson · Answer 1

The correct answer should be B, Let w = the with. the 3w + 8 = length. so the equation is 64 = 2 (3w + 8) + 2w. 64 = 2 (3w + 8) + 2w

Step-by-step explanation:

Perimeter = Length+Length+Width+Width

The Length (L) is + 8 cm bigger then the Width (w) * 3

L = 3W+8

64 = (3W+8) + (3W+8) + W+W

64 = 2 (3W+8) + 2W