The sum of four consecutive integers is 18 find the largest consecutive integer

The largest consecutive integer is 6

Step-by-step explanation:

Let n, n + 1, n+2, and n+3 are the four consecutive integers

The sum of four consecutive integers is 18

n + n + 1 + n + 2 + n + 3 = 18

4n + 6 = 18

4n = 12

n = 3

The sum of four consecutive integers: 3, 4, 5, 6

Answer:

The largest consecutive integer is 6

The sum of 3 consecutive integers can be represented as

X → first integer

X + 1 → second integer

X + 2 → third integer

X + 3 → fourth integer

Since the sum of our three consecutive integers is 18, our equation will read ...

X + X + 1 + X + 2 + X + 3 = 18

If we simplify on the left, our equation will read

4x + 6 = 18 - 6 - 6 ← subtract 6 on both sides 4x = 12 X = 3

X + 3 = largest integer

3 = 3 = 6

Therefore, the largest integer is 6.