Ask Question
12 August, 17:44

One Solution, infinitely many, or no solutions?

x-3y=27,2x=6y-14

+1
Answers (1)
  1. 12 August, 21:25
    0
    Ok, let's take it step by step.

    Take the first equation and solve for x.

    x-3y=27

    x=3y+27

    Substitute x into the second equation.

    2 (3y+27) = 6y-14

    6y+68=6y-14

    68=-14

    Since 68 does not = - 14, the system of equations has no solution.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “One Solution, infinitely many, or no solutions? x-3y=27,2x=6y-14 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers