Find the area of the triangle with A = 60°, b = 11 feet, and c = 8 feet. Round to the nearest tenth.

38.1 sq. ft

Step-by-step explanation:

angle A = 60 deg.

length a = unknown

b = 11 feet

c = 8 feet

angle B must be larger than angle C

try cos A = 8/11? no since cos A = 0.5 so this is not a 30-60-90 triangle

Area of triangle = (1/2) * base * height

height = ...

imagine ... 8 is hypotenuse and then adjacent leg = 8*cos 60

then height = 8 * sin 60 = 8 * (root (3) / 2) = 4*root (3)

Area of triangle A = (1/2) * 11 feet * 4*root (3)

A = 22*root (3) sq. ft. = 38.105 sq. ft = 38.1 sq. ft