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7 February, 23:11

1. Prove that the value of the expression a^2-a is divisible by 2 for any whole value of a.

2. Prove that the sum of three consecutive exponents of the number 2 is divisible by 14.

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  1. 8 February, 01:56
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    in steps

    Step-by-step explanation:

    1. a² - a = a (a - 1) = (a - 1) x a

    since a-1 and a are two consecutive whole number, one of them is "even" whole number. Therefore (a² - a) is divisible by 2 for any whole value of a.

    2. 2ⁿ + 2ⁿ⁺¹ + 2ⁿ⁺² = 2ⁿ⁻¹ x (2 + 2² + 2³) = 2ⁿ⁻¹ x 14

    So, the sum of three consecutive exponents of the number 2 is divisible by 14.
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