a pair of dice is tossed 10 times. what is the possibility that no 7s or 11s appear as the sum of the sides facing up?

It should be 0.08

Explanation: There are six ways to get a 7 and two ways to get an 11 on two dice, and so there are 36 - 8 = 28 ways to get anything else. Therefore, P (no 7 or 11) = P (always getting something else) = (28/36) 10