Find all sets of two consecutive positive odd integers with a sum that is at least 8 and less than 24. Right an inequality for this problem and graph your solution

An odd integer is denoted by 2n+1 where n is an integer.

First odd integer = 2n+1

Next odd integer = 2n+3

8 ≦ (2n+1) + (2n+3) < 24

8 ≦ 2n+1+2n+3 < 24

8 ≦ 4n+4 < 24

Divide through by 4

2 ≦ n+1 < 6

Subtract 1 for all three sides:

1 ≦ n < 5

n ∈ {1,2,3,4}

Answer: {2n+1, 2n+3} {1,3}, {3,5}, {5,7}, {7,9}, (9,11}