Find the solution to the system of equations, x+3y and 2x+4y=8

x = - 7/3y + 8/3

y = - 3/7x + 8/7

Step-by-step explanation:

First, set the equations next to each other to find x and y, I'll start with x:

x + 3y + 2x + 4y = 8

Combine like terms

3x + 7y = 8

Subtract both sides by 7y

3x + 7y - 7y = 8 - 7y

3x = 8 - 7y

I'll re-order the equation to make it easier to divide

3x = - 7y + 8

Divide both sides by 3

3x / 3 = - 7y + 8 / 3

x = - 7/3y + 8/3

If you need decimals just divide with a calculator

Now to find y:

We already combined like terms so we don't need to do that again ...

3x + 7y = 8

Subtract both sides by 3x

3x - 3x + 7y = 8 - 3x

7y = 8 - 3x

I'll reorder the equation once again so the variable comes first

7y = - 3x + 8

Divide both sides by 7

7y / 7 = - 3x + 8 / 7

y = - 3/7x + 8/7

Again, use a calculator to divide completely for decimals.