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14 December, 04:26

The vertex of the graph of a quadratic function is in the second quadrant. The related equation has no real solutions. Which statement is true?

a) The graph opens up.

b) The graph opens down.

c) The y-intercept is 0.

d) The axis of symmetry is x = 0.

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Answers (1)
  1. 14 December, 08:04
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    Answer: a) The graph opens up.

    Step-by-step explanation:

    The vertex is the minimum/maximum of a parabola.

    We know that the vertex is in the second quadrant (so it is in the quadrant of positive y values and negative x values)

    We also know that it has no real roots, so the graph never touches the x-axis, and knowing that the vertex is above the x-axis, then the graph must open upwards.

    Then the correct option is:

    a) The graph opens up.
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