What is the center of a circle represented by the equation (x+9) 2 + (y-6) 2=102? (-9,6) (-6,9) (6,-9) (9,-6)

Question

Mathematics

Terrell Harrington

16 December, 14:55

What is the center of a circle represented by the equation (x+9) 2 + (y-6) 2=102? (-9,6) (-6,9) (6,-9) (9,-6)

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Answers (2)

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Alvaro Horne · Answer 1

Answer: (-9,6)

Step-by-step explanation:

Equation of circle = (x-a) ^2 + (x-b) ^2=r^2

Center of circle = (a, b)

Given equation = (x+9) ^2 + (x-6) ^2=r^2

Comparing both equations we find out that they center Of The given equation is (-9,6)