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19 December, 12:45

Find the 66th term of the following arithmetic sequence. 5,14,23,32, ...

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Answers (2)
  1. 19 December, 12:52
    0
    first term a1 = 5, common difference d = 9

    nth term = a1 + (n - 1) d

    66th term = 5 + (66-1) 9

    = 590 answer
  2. 19 December, 13:07
    0
    5,14,23,32, ...

    n1 = 5

    Common difference = 9 (14 - 5 = 5; 23 - 14 = 9; 32 - 23 = 9; etc ...)

    So formula: An = 5 + 9 (n - 1)

    66th term = 5 + 9 (66 - 1)

    = 5 + 9 (65)

    = 5 + 585

    = 590

    Answer

    590
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