The perimeter of a rectangle is 48 inches and it's length is 4 inches more than it's width what is the area of the rectangle

If the length is w+4 then the equation for the whole perimeter would be 4w+8. 2w+8 for both of the lengths and 2w for both of the widths.

4w+8=48

4w+8-8=48-8

4w=40

4w/4=40/4

w=10

l=10+8, l=18

l x w=a, 18*10=180

The area of the rectangle is 180in^2