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14 February, 20:33

What is the value of A when we rewrite 3.14^159x as A^x?

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  1. 14 February, 21:19
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    The rule we'll use is

    p^ (q*r) = (p^q) ^r

    The exponents have been rearranged a bit.

    In this case, p = 3.14, q = 159 and r = x, so,

    p^ (q*r) = (p^q) ^r

    3.14^ (159*x) = (3.14^159) ^x

    This is in the form A^x with A = 3.14^159
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