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29 October, 19:36

What value (s) of k, where k is an interger, will allow each quadratic equation to be solved by factoring?

x² + kx = 8

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  1. 29 October, 22:54
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    The factored form of the equation x²+kx=8 would be (x+a) (x+b) = 0, with whatever values of a and b make the equation equivalent to x²+kx-8=0.

    So we get k=a+b and ab = (-8).

    Possible integer factors of - 8 are:

    1,-8 or - 1,8, giving k = - 7 or 7 (where's the plus-or-minus?)

    2,-4 (k=-2) or - 2,4 (k=2)

    So possible values of k are - 7, - 2, 2, 7.
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