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16 October, 21:41

Book I, Problem 18. Find three numbers such that thesum of any pair exceeds the third by a given amount; say the given excesses are 20, 30, and 40. [Hint:Letthe sum of all three numbers be 2x. Add number (3) to both sides of the equation (1) C (2) D (3) C20 toget (3) Dx10. Obtain expressions for (1) and (2) similarly.

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  1. 17 October, 00:24
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    25 30 35

    Step-by-step explanation:

    Let the three numbers be represented by a, b, c. Apparently, we want ...

    a + b = c + 20

    a + c = b + 30

    b + c = a + 40

    Adding these three equations gives ...

    2a + 2b + 2c = a + b + c + 90

    Subtracting a+b+c, we have ...

    a + b + c = 90

    __

    Now, we can subtract each original equation from this to find one of the variables:

    (a + b + c) - (a + b) = (90) - (c + 20)

    2c = 70

    c = 35

    (a + b + c) - (a + c) = (90) - (b + 30)

    2b = 60

    b = 30

    c = 90 - 35 - 30 = 25

    The three numbers are 25, 30, 35.
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