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Today, 09:45

Compare the average rate of change for both functions over the interval [0,3].

G (x) = -x^2-5x + 3 and H (x) = - 8x + 10

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  1. Today, 12:34
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    So find g (0) and g (3)

    G (0) = 0^2 - 5 (0) + 3 = 3

    And g (3) = 3^2 - 5 (3) + 3 = 9 - 15 + 3 = 3 so there is no change in g (x) for that interval.

    H (0) = 8 (0) + 10 = 10

    And h (3) = 8 (3) + 10 = 34

    So the change in h (x) for that interval is 24.
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