One number exceeds another by 7 the sum of the numbers 49 what is the number

We can make an algebra problem to solve this. There is a more "hands on" approach, but this is the quickest.

Let x be the first number and let x + 7 be the second number.

x + (x + 7) = 49 (Add the x's)

2x + 7 = 49 (Subtract 7 from both sides to eliminate it from the left)

2x = 42 (divide both sides by 2 to leave x)

x = 21 This will be your first number. Now add 7.

x + 7 = 28 This will be your second number.

Check it:

21 + 28 = 49. Yes!

The answer to your question is well all u have to do is since 7x7=49 u have to find how much it would be so 7+7+7+7+7+7+7