Roy's Used Cars has 12 trucks, 20 cars and 15 SUV's on the lot. If the Roy randomly gives away a vehicle to some lucky customer, what is the probability it is a SUV?

Answer:The probability that Roy gives randomly an SUV = 15 / 47

Step-by-step explanation:

The total number of used cars owned by Roy = 47

[12 trucks + 20 cars + 15 SUV = 47 cars]

The total number in sample space, n (S) = 47

The probability that Roy is giving away and SUV = ?

Let A be the event that Roy is giving an SUV

Total no of SUV's, n (A) = 15

The probability of giving an SUV, P (A) = n (A) / n (S)

P (A) = 15 / 47