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23 December, 04:01

Which shows one way to determine the factors of 4x3 + x2 - 8x - 2 by grouping?

x2 (4x + 1) - 2 (4x + 1)

x2 (4x - 1) + 2 (4x - 1)

4x2 (x + 2) - 1 (x + 2)

4x2 (x - 2) - 1 (x - 2)

+4
Answers (1)
  1. 23 December, 07:22
    0
    Group first 2 and group last 2 and find factors and undistribute

    (4x^3+x^2) + (-8x-2)

    (x^2) (4x+1) + (-2) (4x+1)

    x^2 (4x+1) - 2 (4x+1)

    answer is first one
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