Let f (x) = x2+15x+56

What are the zeros of the function?

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and

-8, - 7

Step-by-step explanation:

f (x) = x^2+15x+56

0 = x^2+15x+56

What two numbers multiply together to make 56 and add together to 15

7*8 = 56

7+8=15

0 = (x+8) (x+7)

Then use the zero product property

x+8 = 0 x+7 = 0

x+8-8 = 0-8 x+7-7 = 0-7

x=-8 x=-7

-7, - 8

Step-by-step explanation:

x² + 15x + 56 = 0

x² + 7x + 8x + 56 = 0

x (x + 7) + 8 (x + 7) = 0

(x + 7) (x + 8) = 0

x = - 7, - 8