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12 January, 05:25

Write a polynomial function of least degree with integral coefficients that have the given zeros. 4,-1,6 f (x) = x^3-9x^2+14x+24

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  1. 12 January, 07:58
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    see explanation

    Step-by-step explanation:

    Given the zeros of a polynomial, say x = a, x = b, x = c

    Then (x - a), (x - b), (x - c) are it's factors

    and the polynomial is the product of the factors

    here x = 4, x = - 1, x = 6, hence

    (x - 4), (x + 1) and (x - 6) are the factors

    f (x) = a (x - 4) (x + 1) (x - 6) ← a is a multiplier

    let a = 1, then expanding the first pair of factors

    f (x) = (x² - 3x - 4) (x - 6) ← expand out the factors

    = x³ - 3x² - 4x - 6x² + 18x + 24 ← collect like terms

    = x³ - 9x² + 14x + 24
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