the length of a rectangle is equal to triple the width. Write a system of equations that can be used to find the dimensions of the rectangle if the perimeter is 88 centimeters. Find the length and the width.

First you set and equation for length which is three times width

l=3w

The substitute in the perimeter, p, into the equation for perimeter which is p=2l+2w

88=2l+2w

Then substitute in length, l, with the equation previously created: l=3w

88=2 (3w) + 2w

Multiply 2 and 3w

88=6w+2w

Combine like terms: 6w+2w

88=8w

Divide to get the value for w

w=11

Since you figure the value for w, 11, you can plug it into the equation for length which is l=3w

l=3 (11)

When you do you get

l=33

So the length is 33 and the width is 11