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6 August, 16:20

How to factor x^3 - 4x^2 - 9x + 36 by grouping

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Answers (2)
  1. 6 August, 16:32
    0
    (x - 4) (x - 3) (x + 3)

    Step-by-step explanation:

    x³ - 4x² - 9x + 36

    x² (x - 4) - 9 (x - 4)

    (x - 4) (x² - 9)

    (x - 4) (x² - 3²)

    (x - 4) (x - 3) (x + 3)
  2. 6 August, 17:15
    0
    (x-4) (x-3) (x+3)

    Step-by-step explanation:

    x^3 - 4x^2 - 9x + 36

    Make 2 groups

    x^3 - 4x^2 - 9x + 36

    We can factor out x^2 from the first group and - 9 from the second group

    x^2 (x-4) - 9 (x-4)

    Now factor out (x-4)

    (x-4) (x^2 - 9)

    This may be an answer choice but we can still factor

    (x^2 - 9) is the difference of squares

    (x^2-9) = (x-3) (x+3)

    Replacing this

    (x-4) (x-3) (x+3)
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