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5 May, 01:13

In the right △ABC, CH is the altitude to the hypotenuse (H∈ AB). Find the ratio of AH:HB, if m∠BAC=30°.

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  1. 5 May, 02:24
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    In a 30°-60°-90° triangle, the hypotenuse is twice the length of the short leg. Here, it is convenient to assign segment BH the length of 1.

    BH is the short leg of ∆BCH, so BC will have length 2.

    BC is the short leg of ∆BAC, so BA will have length 4.

    Now, we have

    ... (AH + HB) : HB = 4 : 1

    So the ratio we want is ...

    ... AH : HB = 3 : 1
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