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6 November, 12:34

A bag contains 9 marbles, of which 3 are red and 6 are blue. players 1 and 2 take turns drawing marbles from the bag without replacement until a red marble is drawn.

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  1. 6 November, 13:36
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    Solution:

    For the first marble chosen by the player1,

    The probability that the marble is red is 3/9=1/3

    After that the second player chose without replacement, there are 8 marbles left, of which 6 are blue. So the probability of the second one being red is 6/8 = 3/4.

    Since the question is asking the probability of both events happening,

    So we have to multiply the two probabilities.

    So the answer is (1/3) * (3/4) = 1/4.
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