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18 December, 04:25

2 (n-1) + 4n = 2 (3n-1)

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  1. 18 December, 05:48
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    infinite solutions

    Step-by-step explanation:

    2 (n-1) + 4n = 2 (3n-1)

    Distribute

    2n - 2 + 4n = 6n - 2

    Combine like terms

    6n - 2 = 6n - 2

    Subtract 6n from each side

    6n-2-6n = 6n-2-6n

    -2 = - 2

    This is always true so there are infinite solutions
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