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7 November, 18:28

Factor completely. 2x^2y + 2xy + 4x + 4 A. (2x + 4) (xy + 1) B. (2x + 4y) (x + 1) C. 2 (xy + 2) (x + 1) D. (2xy + 4) (x + 1)

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  1. 7 November, 20:35
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    2 (xy + 2) (x + 1) (C)

    Step-by-step explanation:

    2x^2y + 2xy + 4x + 4

    = 2xy (x + 1) + 4 (x + 1)

    = (2xy + 4) (x + 1)

    = 2 (xy + 2) (x + 1)
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