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25 March, 01:05

The sum of four consecutive integers is 266. What are the integers?

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Answers (2)
  1. 25 March, 04:23
    0
    The 4 consecutive integers are 65,66,67,68

    Step-by-step explanation:

    Ok so there are 4 different numbers and they are consecutive, so you'd start of like:

    266 = n + (n+1) + (n+2) + (n+3). Next you would collect like terms to simplify ...

    266=4n+6. Next you want to solve for n ...

    266-6=4n+6-6

    260=4n

    260/4=4n/4

    65=n ... so you have n. hurray, but you need the other three numbers ... so just substitute 65 as n in the formula:

    266=65 + (65+1) + (65+2) + (65+3)

    266=65+66+67+68

    266=266 both sides are equal so it means the equation is solved. The 4 consecutive integers are 65,66,67,68
  2. 25 March, 04:47
    0
    Let the four consecutive integers are x, x + 1, x + 2, x + 3.

    According to the question,

    Sum of four consecutive integers = 266. [ Given ]

    ⇒ x + x + 1 + x + 2 + x + 3 = 266

    ⇒ 4x + 6 = 266

    ⇒ 4x = 260

    ⇒ x = 260/4

    ⇒ x = 65

    Integers are:

    x = 65

    x + 1 = 65 + 1 = 66

    x + 2 = 65 + 2 = 67

    x + 3 = 65 + 3 = 68
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