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28 November, 20:03

Given y=x^3-2x^2-15; find the relative minimum.

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  1. 28 November, 20:30
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    The min is at x=4/3

    Step-by-step explanation:

    Take the first derivitave. Set that equation equal to zero. Then take the second derivative. Take the x values and put them into the second derivative. If the value is +, that means a rel min. If it is -, that means rel max.
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