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7 November, 18:29

The height above the ground (in feet) of a ball dropped from the top of a 30-foot-tall building after t seconds is given by the polynomial - 16t^2 + 30. What is the height of the ball after 1/2 second?

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  1. 7 November, 20:47
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    The height h above ground in feet of a ball dropped from the top of a 30 foot tall building after t seconds is given by the polynomial: h (t) = - 16t^2+30. what is the height of the ball after 1/2 second?

    h (t) = - 16t^2+30

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    Sub 1/2 for t to find h (1/2)
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