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19 December, 13:09

Got a fairly simple looking system of equations, 2k+4y=20, and 3x+6y=30 Don't understand how to prove what values of k provide - 1 solution - no solutions - and many solutions

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  1. 19 December, 14:29
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    2kx+4y=20 ⇒ kx+2y=10

    3x+6y=30 ⇒ x+2y = 10

    k is the coefficient of x, so it is the slope of the line

    when k=1, both equations will be same, then there are many solutions when k=0 there is one solution when k is anything different, then the lines will be parallel, so no solutions
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